Acoustics & Music Theory
why it sounds like that
Generator

The end correction, for a bore of radius 7.5 mm

How flat a tube sounds against what its physical length alone would predict, because the wave carries on past the opening before it turns round. The correction is 4.6 mm at every note — Levine and Schwinger's 0.6133 times the radius for an unflanged end — and the error it causes is 13 cents on a 60 cm sounding length and 52 cents on 15 cm. It is the same millimetres in both cases.
The end correction, for a bore of radius 7.5 mmHow flat a tube sounds against what its physical length alone would predict, because the wave carries on past the opening before it turns round. The correction is 4.6 mm at every note — Levine and Schwinger's 0.6133 times the radius for an unflanged end — and the error it causes is 13 cents on a 60 cm sounding length and 52 cents on 15 cm. It is the same millimetres in both cases.13¢60 cm26¢30 cm52¢15 cm0.200.400.600.80020406080100sounding length, metrescents flat4.6 mmadded to everylength equally— which is alarger fractionof a shorter tubeLevine & Schwinger,1948

Drawn above with its standard settings, which is almost never how an essay draws it: an essay states the numbers it is arguing about, so the figure a reader meets there is about that argument rather than about the drawing in general. Every option a placement passes is checked against the ones this function actually reads, because an option it does not read is silently ignored and the figure quietly draws what is above instead.

It makes a noise. 10 of its 10 placements carry sound, built from the same numbers as the drawing, offering these buttons: A stopped tube 0.3 m long, sounding 286 Hz, against the pitch its length alone predicts: 103.0 cents, A stopped tube 0.3 m long, sounding 286 Hz, against the pitch its length alone predicts: 26.3 cents, A stopped tube 0.45 m long, sounding 191 Hz, against the pitch its length alone predicts: 17.6 cents, A stopped tube 0.6 m long, sounding 143 Hz, against the pitch its length alone predicts: 13.2 cents, A stopped tube 0.6 m long, sounding 143 Hz, against the pitch its length alone predicts: 52.3 cents, A stopped tube 0.66 m long, sounding 130 Hz, against the pitch its length alone predicts: 12.0 cents, A stopped tube 0.8 m long, sounding 107 Hz, against the pitch its length alone predicts: 80.4 cents, A stopped tube 1.1 m long, sounding 78 Hz, against the pitch its length alone predicts: 58.8 cents and 6 more.

Called by 5 essays

the blast radius of changing it

The end correction, for a bore of radius 7.5 mm. How flat a tube sounds against what its physical length alone would predict, because the wave carries on past the opening before it turns round. The correction is 4.6 mm at every note — Levine and Schwinger's 0.6133 times the radius for an unflanged end — and the error it causes is 13 cents on a 60 cm sounding length and 52 cents on 15 cm. It is the same millimetres in both cases.

The tube ends after it ends

A wave does not turn round at the opening. It carries on into the room for about six-tenths of the bore radius and reflects there, so every tube is acoustically longer than it is. The correction is a fixed number of millimetres against a wavelength that halves every octave — a rounding error at the bottom of an instrument's range and most of a semitone at the top.

instruments · Air column One register vent, 12 fingerings. Where the second mode's pressure node sits for each fingering of a stopped tube, against a single register hole drilled 12 cm from the mouthpiece. The node is a third of the way along the sounding length, so it moves every time a hole is opened, and the vent's error runs from -38 to -1 cents across the range. A perfect register system would need one hole per fingering. The number of holes actually fitted is one, and the leftover is a design decision rather than a fault.

One hole doing a dozen jobs

A register key works by forcing a pressure node where the second mode already has one, which kills the fundamental and leaves the mode above. The node sits a fixed fraction along the sounding length — and the sounding length changes with every fingering, while the hole stays where it was drilled. The leftover error is computable, and it is why the throat notes are the ones players complain about.

instruments · Tone holes What gets out of an opening, for 4 openings. The fraction of the wave's energy radiated at an open end against frequency, in the baffled-piston model — the radiation resistance of a circular piston, normalised to the tube's own impedance. Each curve runs from nothing at the bottom, where the opening is far smaller than a wavelength and the wave simply turns round, to everything above ka ≈ 2. Half the energy leaves at 6364 Hz for a flute's embouchure end (radius 10 mm), 2015 Hz for a clarinet's bell (radius 30 mm), 975 Hz for a trumpet's bell (radius 62 mm), 403 Hz for a horn's bell (radius 150 mm). The crossover goes as one over the radius, so the widest and narrowest here are 15.8 times apart in frequency. The same number decides how strongly the tube resonates and how much sound it makes, which is why a bell cannot brighten an instrument without also weakening its own resonances.

The bell decides what gets out

A tube resonates because the wave turns round at the open end, and it is audible because some of the wave does not. Those are the same number with opposite signs. One quantity — the size of the opening against a wavelength — decides how loud an instrument is, how bright it is and how directional it is, and a bell moves the boundary rather than removing it.

timbre · Air column What a hand in the bell buys, and what it costs. How far the instrument flattens and how much radiation it loses, against the share of the bell's mouth the hand blocks, for an F horn's 15 centimetre mouth on a 3.7 metre acoustic length. The two curves are the same aperture radius read twice: a narrower mouth adds inertance, which lengthens the tube, and is acoustically smaller, which stops radiating. The mark is the 25.6 cents left owed earlier on the eleventh partial — it needs 62 per cent of the mouth blocked and costs 3.8 decibels of radiated power. Fully stopping is a semitone and nine decibels.

The hand that changes the bore

A conjecture refuted here left a question with a number on it: the natural trumpet's eleventh partial is 48.7 cents flat, the lips can move it 23.1, and 25.6 cents are owed by something that is not an embouchure. There is exactly one thing a player can change about the bore while playing, and putting the hand in the bell buys those 25.6 cents at a cost of 3.8 decibels — because the aperture that tunes the instrument is the aperture that radiates it.

tuning · Air column cylinder and Bessel flare: the length each mode behaves as though it has. Each mode's own acoustic length, m·c over twice its frequency, for a bore 148 cm long. A cylinder would give one number repeated. This gives 164 cm at the second mode and 154 at the 8th — a spread of 10.1 centimetres, or 110 cents, because a flare's end correction is a length that shrinks as the note rises. The first mode is off the top of this axis and is not a mode a player uses.

A horn has one length per partial

Every tube until now has had an acoustic length: its physical length plus a correction for the wave carrying on past the opening. A flaring bore does not have one. Its second mode behaves as though the tube were 164 centimetres long and its eighth as though it were 154, and the ten centimetres between them are the same physical fact — a fixed correction against a shrinking wavelength — arriving as a hundred cents.

tuning · Bore profile

All figures · What can be heard